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Hello,
The "Netz Noe" uses some strange encrypted mbus communication. I was able to decrypt the payload. but i cant get the XML of the decrypted APU. The Online Transltor at https://www.gurux.fi/GuruxDLMSTranslator can convert it to xml.
Here is the used code and the output from Online Translator:
tr = GXDLMSTranslator(TranslatorOutputType.SIMPLE_XML)
daten = recv(ser).hex()
if (daten == '' or daten[0:8] != "68010168"):
continue
print ("Daten: ", daten);
systemTitel = daten[22:38]
frameCounter = daten[44:52]
frame = daten[52:560]
frame = unhexlify(frame)
encryption_key = unhexlify(evn_schluessel)
init_vector = unhexlify(systemTitel + frameCounter)
cipher = AES.new(encryption_key, AES.MODE_GCM, nonce=init_vector)
apdu = cipher.decrypt(frame)
print("APDu: ", apdu.hex())
print("MessageToXml: ",tr.messageToXml(apdu.hex()))
--> Invalid DLMS framing.
APDu: 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
Result from Online Translator:
<DataNotification>
<LongInvokeIdAndPriority Value="80230672" />
<!--2021-12-08 13:12:10-->
<DateTime Value="07E50C08030D0C0A00FFC402" />
<NotificationBody>
<DataValue>
<Structure Qty="23" >
<!--2021-12-08 13:12:10-->
<OctetString Value="07E50C08030D0C0A00FFC402" />
<!--1.0.1.8.0.255-->
<OctetString Value="0100010800FF" />
<UInt32 Value="0054D1A4" />
<Structure Qty="02" >
<Int8 Value="00" />
<Enum Value="1E" />
</Structure>
<!--1.0.2.8.0.255-->
<OctetString Value="0100020800FF" />
<UInt32 Value="00557DA8" />
<Structure Qty="02" >
<Int8 Value="00" />
<Enum Value="1E" />
</Structure>
<!--1.0.1.7.0.255-->
<OctetString Value="0100010700FF" />
<UInt32 Value="000003F2" />
<Structure Qty="02" >
<Int8 Value="00" />
<Enum Value="1B" />
</Structure>
<!--1.0.2.7.0.255-->
<OctetString Value="0100020700FF" />
<UInt32 Value="0000005F" />
<Structure Qty="02" >
<Int8 Value="00" />
<Enum Value="1B" />
</Structure>
<!--1.0.32.7.0.255-->
<OctetString Value="0100200700FF" />
<UInt16 Value="0925" />
<Structure Qty="02" >
<Int8 Value="FF" />
<Enum Value="23" />
</Structure>
<!--1.0.52.7.0.255-->
<OctetString Value="0100340700FF" />
<UInt16 Value="092A" />
<Structure Qty="02" >
<Int8 Value="FF" />
<Enum Value="23" />
</Structure>
<!--1.0.72.7.0.255-->
<OctetString Value="0100480700FF" />
<UInt16 Value="0935" />
<Structure Qty="02" >
<Int8 Value="FF" />
<Enum Value="23" />
</Structure>
<!--1.0.31.7.0.255-->
<OctetString Value="01001F0700FF" />
<UInt16 Value="00DE" />
<Structure Qty="02" >
<Int8 Value="FE" />
<Enum Value="21" />
</Structure>
<!--1.0.51.7.0.255-->
<OctetString Value="0100330700FF" />
<UInt16 Value="0191" />
<Structure Qty="02" >
<Int8 Value="FE" />
<Enum Value="21" />
</Structure>
<!--1.0.71.7.0.255-->
<OctetString Value="0100470700FF" />
<UInt16 Value="005C" />
<Structure Qty="02" >
<Int8 Value="FE" />
<Enum Value="21" />
</Structure>
<!--1.0.13.7.0.255-->
<OctetString Value="01000D0700FF" />
<Int16 Value="02D3" />
<Structure Qty="02" >
<Int8 Value="FD" />
<Enum Value="FF" />
</Structure>
<OctetString Value="31373832574343DEC9CE1ECB" />
</Structure>
</DataValue>
</NotificationBody>
</DataNotification>
Any Help would be much appreciated. TIA
Rufinus
Hi,
Hi,
You are using messageToXml, but you have removed the frame and you have PDU.
You need to use pduToXml to convert PDU to XML.
Peplace this line:
print("MessageToXml: ",tr.messageToXml(apdu.hex()))
with this:
print("PDUToXml: ", tr.pduToXml(apdu.hex()))
BR,
Mikko
hi,
hi,
thanks. I swear i had pduToXml as i started and it wasnt working. no it does.
Thanks for the pointer.
Hi,
Hi,
You can also use findNextFrame to find frames from the byte stream.
If you set systemTitle, blockCipherKey and authenticationKey for the XML parser it will encrypt the data for you.
Your solution will work now, but it doesn't work when you have more complex data or if you want to use HDLC framing.
BR,
Mikko