Not able to read one byte data, if terminator is 0x03

actually i have made a function for receiving the data. I forget to mention that i am using Eop=(byte)0x03 by passing it into the method. I am using Gurux.Common.dll and Gurux.Serial.dll
Below the code for receiving function.

public byte[] ReadDataPacket(byte[] data, int tryCount, byte eop)
{
if (data == null)
{
return null;
}
int pos = 0;
bool succeeded = false;
Gurux.Common.ReceiveParameters<byte[]> p = new ReceiveParameters<byte[]>
{
Eop = eop,
WaitTime =2000,
};
lock (Form1.gxSerial1.Synchronous)
{
if (data != null)
{
Form1.gxSerial1.Send(data);
}
System.Threading.Thread.Sleep(100);
while (!succeeded && pos != 3)
{
succeeded = Form1.gxSerial1.Receive(p);
if (!succeeded)
{
//Try to read again...
if (++pos != tryCount)
{
//If Eop is not set read one byte at time.
if (p.Eop == null)
{
p.Count = 1;
}
System.Diagnostics.Debug.WriteLine("Data send failed. Try to resend " + pos.ToString() + "/3");
Form1.gxSerial1.Send(data);
continue;
}
string err = "Failed to receive reply from the device in given time.";
throw new Exception(err);
}
}

}
return p.Reply;
}

yes, meter is sending 0x03, It is a NON-DLMS.

Thanks sir, issue is resolved for 1 byte, now i am able to read data which is 0x03.
But now i am facing a another issue when the terminator byte 0x03 occurs in the mid of data, then i didn't get the full data in output.

This is output data which i should get in the output
02 00 00 03 E7 EA 03

but i am getting output
02 00 00 03
last three byte has been left out due to 0x03 terminator byte occurs in mid of data.

How can i solve this issue if terminator byte occurs in the mid of data as data part.